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I'm trying to find the mean,range,mode and standard deviation of a sample
Solved by V. J. in 29 mins
Information from the American institute of insurance indicates the mean amount of life insurance per household in the United States is \$110,000 with a standard deviation of \$40,000. Assume the population distribution is normal. A random sample of 100 households is taken. (a) What is the probability that sample mean will be more than \$120,00? (b) What is the probability that sample mean will be between \$100,000 and \$120,000? Round your answer to 4 decimal places. ( use part 2 sheet to answer this question)
Solved by F. Y. in 19 mins
Now use the RANDBETWEEN function in Microsoft Excel to select two simple random samples of 10 days sample and 500 days sample from the population. Using just your samples, calculate the mean, median, standard deviations and mode if applicable for each random sample. [20%].
Solved by D. S. in 26 mins
use the excel sheet name part 2 to answer the question and round the answer to 4 decimal places . Information from the American institute of insurance indicates that mean amount of life insurance per household in the united states is \$100,000 with a standard deviation of \$40,000 assume the population distribution is normal. A random sample of 100 household is taken What is the probability that sample mean will be more than \$120,000? What is the probability that sample mean will be between \$100,000 and \$120,000?
Solved by B. Y. in 21 mins
In cell B2, calculate the probability of selling the exact number of products calculated in cell A2, using the normal distribution function and the mean and sample standard deviation calculated in the prior step.
Solved by K. L. in 13 mins