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=MEDIAN(IF(AND(E4:E25="US",$D$4:$D$25="MD"),$F$4:$F$25,))
Solved by T. S. in 17 mins
I am trying out a formula I saw in google but its not working in my excel and producing an error. Can you please help me? =(NETWORKDAYS(StartDT,EndDT)-1)*(StopTime-StartTime)+IF(NETWORKDAYS(EndDT,EndDT),MEDIAN(MOD(EndDT,1),StopTime,StartTime),StopTime)-MEDIAN(NETWORKDAYS(StartDT,StartDT)*MOD(StartDT,1),StopTime,StartTime)
Solved by T. U. in 29 mins
I'm looking for a formula that will help me find anomalies in my Median column if the calculated value is 35% above the median then consider it as an anomaly
Solved by M. Q. in 19 mins
i have this formula currently which works but not if I want it for every day - any ideas ?? (NETWORKDAYS.INTL(L1362,M1362,11,BH!A:A)-1)*("17:30"-"8:30")+IF(NETWORKDAYS.INTL(M1362,M1362,11,BH!A:A),MEDIAN(MOD(M1362,1),"8:30","17:30"),"17:30")-MEDIAN(NETWORKDAYS.INTL(L1362,L1362,11,BH!A:A)*MOD(L1362,1),"8:30","17:30")
Solved by A. D. in 14 mins
i am having trouble with a median calculation with nested if criteria. i need to find the median sales price within a date range. last time i tried excelchat was having technical issues with downloading so trying again.
Solved by B. B. in 25 mins